WebAug 26, 2024 · Best answer. Sn = n (4n + 1) Sn - 1 = (n - 1) [ 4 (n - 1) - 1] = (n - 1) [ 4n - 5] Sn - Sn - 1 = n (4n + 1) - (n - 1) (4n - 5) (a1 + a2 + a3 + - - - + an - 1 + an) - (a1 + a2 + a3 + - - - + … WebAP®︎/College Calculus BC. ... trying that out, I took the derivative of Sn using the quotient rule to try to find a(n) And that's where I think you find the fundamental difference …
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WebMar 30, 2024 · The sum of first n terms of an AP is given by S n = 2n 2 + 3n . Find the sixteenth term of the AP. Find the sixteenth term of the AP. This is a question of CBSE Sample Paper - Class 10 - 2024/18. WebSep 20, 2024 · Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 …
WebIf S n, the sum of first n terms of an AP is given by Sn = 3n 2 - 4n, find the nth term. Advertisement Remove all ads Solution We have, S n = 3n 2 - 4n for n = 1 ⇒ S 1 = 3 ( 1) 2 - 4 ( 1) = 3 - 4 = - 1 ⇒ a 1 = S1 = -1 for n = 2 ⇒ S 2 = 3 ( 2) 2 - 4 ( 2) = 12 - 8 = 4 S 2 = 4 a 2 = S 2 - S 2 = 4 - (-1) a 2 = 5 Common difference, d = a 2 - a 1 WebMay 7, 2024 · (b) In an AP if Sn = n (4n + 1), then find the AP. cbse class-10 1 Answer +1 vote answered May 7, 2024 by AnantShaw (45.9k points) selected May 8, 2024 by …
WebWe know that, the nth term of an AP is; an= Sn−Sn−1. an= n(4n+1)−(n−1){4(n−1)+1} [∵ Sn= n(4n+1)] ⇒ an =4n2+n−(n−1)(4n−3) ⇒ an =4n2+n−4n2+3n+4n−3. ⇒ an =8n−3. P utn=1,⇒ … WebJan 20, 2014 · We have, S n = 4n 2 + n put n = 1, we get S 1 = 4(1) 2 + 1 = 4 + 1 = 5 So, First term, a 1 = 5 Put n = 2 , we get S 2 = 4(2) 2 + 2 = 18 so, a 2 = S 2 - S 1 = 18 - 5 = 13 Put n = 3, we get S 3 = 4(3) 2 + 3 = 39 a 3 = S 3 - S 2 = 39 - 18 = 21 So, the required AP is 5, 13, 21, .....
WebFeb 5, 2024 · if the sum of n terms of an AP is given by Sn=n (4n+1),then find the nth term of the AP - Brainly.in 05.02.2024 Math Secondary School answered If the sum of n terms of an AP is given by Sn=n (4n+1),then find the nth term of the AP See answers Advertisement ideba2011 Answer:given below Step-by-step explanation: follow the steps..... Advertisement
WebSep 20, 2024 · Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 (2)-3 =13 so, AP is 5, 13 , 21 and so on Find Math textbook solutions? Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 solutions crypton furniture reviewsWebNCERT Exemplar Class 10 Maths Exercise 5.3 Sample Problem 1. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, find the value of n. Summary: An arithmetic progression is a sequence where each term, except the first term, is obtained by adding a fixed number to its previous term. If the numbers n - 2, 4n - 1 and 5n + 2 are in AP, then the value ... dusty soft summer colorsWeb0001493152-23-011890.txt : 20240412 0001493152-23-011890.hdr.sgml : 20240412 20240411201147 accession number: 0001493152-23-011890 conformed submission … dusty soul food matteson il hoursWebJan 28, 2024 · #class10#arithmeticprogressionsIn an AP, if Sn = n (4n + 1), find the AP crypton future media addressWebMar 29, 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. dusty springfield - anyone who had a heartWebG@ Bð% Áÿ ÿ ü€ H FFmpeg Service01w ... crypton future media englishWebApr 14, 2024 · I#H"ÿ÷†¿O#N"ÿ÷‚¿ ´ j F@x F ( Ñ F]ø K ði½¡j`j 1]ø K ðq½ ´ F Fjbx * Ñ]ø Kÿ÷r¼¡j F`j 1]ø K ð^½pµ F F)-ÐÊ ÕƒjI [khj½èp@ G‹ Ð ð , Ð , Ð ) Ѓjɲ@j k½èp@ G½èp@ÿ÷É¿ƒj›kâçƒj hÛh@j˜G"y K!F(FSø"0×çp½d‡ -é÷O F F F F(Fþ÷ ÿ ±Î¹£j9F›nLà(Fþ÷‰ÿ ±†±õç-UЫ SÑkhOê +Û² … dusty springfield all i see is you